int n = 1;
while (n <= 5) {
cout << n << " ";
n++;
}
// Output: 1 2 3 4 5
int x = 10;
do {
cout << x;
x++;
} while (x < 5);
// Output: 10 (ran once even though x > 5 already)
int num = 12345, count = 0;
while (num > 0) {
count++;
num /= 10; // removes last digit
}
// count == 5
Write sumDigits(int n) that returns the sum of all digits of n.
Example: sumDigits(123) → 6 (1+2+3).
Hint: n % 10 gives the last digit, n / 10 removes it.
Click "Run" to execute your code.